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प्रश्न
Solve for x:
`"p"^-5 = (1)/"p"^(x + 1)`
योग
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उत्तर
`"p"^-5 = (1)/"p"^(x + 1)`
⇒ p-5 x px + 1 = 1
⇒ `"p"^(-5 + x +1)` = 1
⇒ px-4 = p0
⇒ x - 4 = 0
⇒ x = 4.
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Solving Exponential Equations
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