Solve for X: P − 5 = 1 P X + 1 - Mathematics

Solve for x:

`"p"^-5 = (1)/"p"^(x + 1)`

बेरीज

`"p"^-5 = (1)/"p"^(x + 1)`
⇒ p^-5 x p^{x + 1} = 1
⇒ `"p"^(-5 + x +1)` = 1
⇒ p^x-4= p⁰
⇒ x - 4 = 0
⇒ x = 4.

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Solving Exponential Equations

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पाठ 9: Indices - Exercise 9.1

पाठ 9 Indices
Exercise 9.1 | Q 9.08

Solve for x:

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1 = p^x

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