Solve for X: P − 5 = 1 P X + 1

Solve for x:

`"p"^-5 = (1)/"p"^(x + 1)`

Sum

`"p"^-5 = (1)/"p"^(x + 1)`
⇒ p^-5 x p^{x + 1} = 1
⇒ `"p"^(-5 + x +1)` = 1
⇒ p^x-4= p⁰
⇒ x - 4 = 0
⇒ x = 4.

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Solving Exponential Equations

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Chapter 6: Indices - Exercise 9.1

Chapter 6 Indices
Exercise 9.1 | Q 9.08

Solve : 4^{x - 2} - 2^{x + 1} = 0

If a^x = b, b^y = c and c^z = a, prove that : xyz = 1.

Evaluate : `[(-2/3)^-2]^3 xx (1/3)^-4 xx 3^-1 xx 1/6`

Solve : 3^x-1× 5^2y-3 = 225.

If 2^x = 4^y = 8^z and `1/(2x) + 1/(4y) + 1/(8z) = 4` , find the value of x.

Solve for x:
2^2x+1= 8

Solve for x:
2^2x + 2^{x +2} - 4 x 2³ = 0

Solve for x:
5^x2 : 5^x= 25 : 1

Solve for x:

`sqrt((8^0 + 2/3)` = (0.6)^2-3x

Find the value of 'a' and 'b' if:

`(sqrt243)^"a" ÷ 3^("b" + 1)` = 1 and `27^"b" - 81^(4 -"a"/2)` = 0