Advertisements
Advertisements
प्रश्न
Find x, if : `sqrt( 2^( x + 3 )) = 16`
Advertisements
उत्तर
`sqrt( 2^( x + 3 )) = 16`
`( 2^( x + 3 ))^(1/2) = 2 xx 2 xx 2 xx 2`
⇒ `( 2 )^[(x + 3)/2] = 2^4`
We know that if bases are equal, the powers are equal.
⇒ `[ x + 3 ]/2 = 4`
⇒ x + 3 = 8
⇒ x = 8 - 3
⇒ x = 5
APPEARS IN
संबंधित प्रश्न
Solve for x : 9x+2 = 720 + 9x
Solve x and y if : ( √32 )x ÷ 2y + 1 = 1 and 8y - 164 - x/2 = 0
Solve : 3x-1× 52y-3 = 225.
Evaluate : `4/(216)^(-2/3) + 1/(256)^(-3/4) + 2/(243)^(-1/5)`
Evaluate the following:
`(2^3 xx 3^5 xx 24^2)/(12^2 xx 18^3 xx 27)`
Evaluate the following:
`16^(3/4) + 2(1/2)^-1 xx 3^0`
Solve for x:
22x+3 - 9 x 2x + 1 = 0
Solve for x:
9x+4 = 32 x (27)x+1
If `x^(1/3) + y^(1/3) + z^(1/3) = 0`, prove that (x + y + z)3 = 27xyz
Prove the following:
`("a"^"m"/"a"^"n")^("m"+"n"+1) ·("a"^"n"/"a"^1)^("n" + 1-"m").("a"^1/"a"^"m")^(1+"m"-"n")`
