Advertisements
Advertisements
प्रश्न
Find x, if : `( sqrt(3/5))^( x + 1) = 125/27`
Advertisements
उत्तर
`( sqrt(3/5))^( x + 1) = 125/27`
⇒ `[(3/5)^(1/2)]^( x + 1 ) = [ 5 xx 5 xx 5 ]/[ 3 xx 3 xx 3]`
⇒ `(3/5)^[( x + 1 )/2] = (5/3)^3`
⇒ `(3/5)^[( x + 1 )/2] = (3/5)^- 3`
We know that if bases are equal, the powers are equal
⇒ `[ x + 1 ]/2 = -3`
⇒ x + 1 = - 6
⇒ x = - 6 - 1
⇒ x = - 7
APPEARS IN
संबंधित प्रश्न
Solve : 8 x 22x + 4 x 2x + 1 = 1 + 2x
Solve:
22x + 2x+2 − 4 × 23 = 0
Solve for x:
`(81)^(3/4) - (1/32)^(-2/5) + x(1/2)^(-1).2^0 = 27`
If 5x + 1 = 25x - 2, find the value of 3x - 3 × 23 - x.
Solve x and y if : ( √32 )x ÷ 2y + 1 = 1 and 8y - 164 - x/2 = 0
Simplify : `[ 3 xx 9^( n + 1 ) - 9 xx 3^(2n)]/[3 xx 3^(2n + 3) - 9^(n + 1 )]`
Evaluate the following:
`(12^2 xx 75^-2 xx 35 xx 400)/(48^2 xx 15^-3 xx 525)`
Evaluate the following:
`(27)^(2/3) xx 8^((-1)/6) ÷ 18^((-1)/2)`
Solve for x:
9 x 81x = `(1)/(27^(x - 3)`
If 2400 = 2x x 3y x 5z, find the numerical value of x, y, z. Find the value of 2-x x 3y x 5z as fraction.
