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प्रश्न
Solve for x:
9 x 81x = `(1)/(27^(x - 3)`
बेरीज
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उत्तर
9 x 81x = `(1)/(27^(x - 3)`
⇒ 32 x 34x = `(1)/(3^3(x - 3)`
⇒ 32 x 34x = `(1)/(3^(3x - 9)` .....(Using (am)n = amn)
⇒ 32 x 34x x 33x-9 = 1
⇒ `3^(2+ 4+3x-9)` = 1 x 30
⇒ 2 + 4 + 3x - 9 = 0
⇒ 3x - 3 = 0
⇒ x = 1.
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Solving Exponential Equations
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