Advertisements
Advertisements
प्रश्न
Evaluate the following:
`9^(5/2) - 3 xx 5^0 - (1/81)^((-1)/2)`
योग
Advertisements
उत्तर
`9^(5/2) - 3 xx 5^0 - (1/81)^((-1)/2)`
= `3^(2 xx 5/2) - 3 xx 1 - (1/81)^((-1)/2)`
= `3^5 - 3 - 9^(2 xx 1/2)`
= 243 - 3 - 9
= 231.
shaalaa.com
Solving Exponential Equations
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
APPEARS IN
संबंधित प्रश्न
Solve for x:
`3^(4x + 1) = (27)^(x + 1)`
Solve for x : (49)x + 4 = 72 x (343)x + 1
Find x, if : `sqrt( 2^( x + 3 )) = 16`
Solve : 8 x 22x + 4 x 2x + 1 = 1 + 2x
If m ≠ n and (m + n)-1 (m-1 + n-1) = mxny, show that : x + y + 2 = 0
Evaluate : `[(-2/3)^-2]^3 xx (1/3)^-4 xx 3^-1 xx 1/6`
Solve for x:
22x+3 - 9 x 2x + 1 = 0
Solve for x:
`"p"^-5 = (1)/"p"^(x + 1)`
Solve for x:
`sqrt((3/5)^(x + 3)) = (27^-1)/(125^-1)`
Prove the following:
`(x^("a"+"b")/x^"c")^("a"-"b") · (x^("c"+"a")/(x^"b"))^("c"-"a") · ((x^("b"+"c"))/(x"a"))^("b"-"c")` = 1
