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प्रश्न
Evaluate the following:
`(27)^(2/3) xx 8^((-1)/6) ÷ 18^((-1)/2)`
योग
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उत्तर
`(27)^(2/3) xx 8^((-1)/6) ÷ 18^((-1)/2)`
= `3^(3 xx 2/3) xx (1)/(2^(3 xx 1/6)) ÷ (1/18)^(1/2)`
= `(3^2)/(2^(1/2)) xx (2 xx 3^2)^(1/2)`
= `(3^2)/(2^(1/2)) xx 2^(1/2) xx 3`
= `3^(2 + 1)`
= 33
= 27.
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Solving Exponential Equations
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