Advertisements
Advertisements
प्रश्न
Evaluate the following:
`(27)^(2/3) xx 8^((-1)/6) ÷ 18^((-1)/2)`
योग
Advertisements
उत्तर
`(27)^(2/3) xx 8^((-1)/6) ÷ 18^((-1)/2)`
= `3^(3 xx 2/3) xx (1)/(2^(3 xx 1/6)) ÷ (1/18)^(1/2)`
= `(3^2)/(2^(1/2)) xx (2 xx 3^2)^(1/2)`
= `(3^2)/(2^(1/2)) xx 2^(1/2) xx 3`
= `3^(2 + 1)`
= 33
= 27.
shaalaa.com
Solving Exponential Equations
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
APPEARS IN
संबंधित प्रश्न
Find x, if : 42x = `1/32`
Solve : 4x - 2 - 2x + 1 = 0
Solve for x : 9x+2 = 720 + 9x
Solve for x : (a3x + 5)2. (ax)4 = a8x + 12
Evaluate the following:
`(4^3 xx 3^7 xx 5^6)/(5^8 xx 2^7 xx 3^3)`
Evaluate the following:
`(2^6 xx 5^-4 xx 3^-3 xx 4^2)/(8^3 xx 15^-3 xx 25^-1)`
Evaluate the following:
`16^(3/4) + 2(1/2)^-1 xx 3^0`
Solve for x:
22x+1= 8
Solve for x:
22x + 2x +2 - 4 x 23 = 0
If 2x = 3y = 12z ; show that `(1)/z = (1)/y + (2)/x`.
