Advertisements
Advertisements
प्रश्न
If 2x = 3y = 12z ; show that `(1)/z = (1)/y + (2)/x`.
Advertisements
उत्तर
Let 2x = 3y = 12z = k
⇒ `2 = "k"^(1/x), 3 = "k"^(1/y), 12 = "k"^(1/z)`
Now , 12 = 2 x 2 x 3
⇒ `"k"^(1/z) = "k"^(1/x) xx "k"^(1/x) xx "k"^(1/y)`
⇒ `(1)/z = (1)/x + (1)/x + (1)/y`
⇒ `(1)/z = (2)/x + (1)/y`.
APPEARS IN
संबंधित प्रश्न
Solve for x : (49)x + 4 = 72 x (343)x + 1
Solve : `(sqrt(3))^( x - 3 ) = ( root(4)(3))^( x + 1 )`
If m ≠ n and (m + n)-1 (m-1 + n-1) = mxny, show that : x + y + 2 = 0
Solve for x:
1 = px
Find the value of k in each of the following:
`root(4)root(3)(x^2)` = xk
If x = `3^(2/3) + 3^(1/3)`, prove that x3 - 9x - 12 = 0
Show that : `(1)/(1 + "a"^("p"- "q")) + (1)/(1 + "a"^("q"- "p")`
If 2250 = 2a. 3b. 5c, find a, b and c. Hence, calculate the value of 3a x 2-b x 5-c.
Find the value of 'a' and 'b' if:
92a = `(root(3)(81))^(-6/"b") = (sqrt(27))^2`
Find the value of 'a' and 'b' if:
`(sqrt243)^"a" ÷ 3^("b" + 1)` = 1 and `27^"b" - 81^(4 -"a"/2)` = 0
