Advertisements
Advertisements
प्रश्न
Find the value of 'a' and 'b' if:
92a = `(root(3)(81))^(-6/"b") = (sqrt(27))^2`
Advertisements
उत्तर
92a = `(root(3)(81))^(-6/"b") = (sqrt(27))^2`
⇒ 92a = `(root(3)(3^4))^(-6/"b") = (sqrt(3^3))^2`
⇒ (32)2a = `(3^(4xx1/3))^(-6/"b") = (3^(3xx1/2))^2`
⇒ 34a = `(3^1)^(-8/"b") = (3^1)^3`
⇒ 34a = `(-8)/"b" = 3`
⇒ 34a = 3 and `(-8)/"b"` = 3
⇒ 4a = 3 and b = `(-8)/(3)`
⇒ `"a" = (3)/(4) and "b" = (-8)/(3)`.
APPEARS IN
संबंधित प्रश्न
Evaluate : `[(-2/3)^-2]^3 xx (1/3)^-4 xx 3^-1 xx 1/6`
Solve : 3x-1× 52y-3 = 225.
Solve for x:
2x + 3 + 2x + 1 = 320
Solve for x:
1 = px
Solve for x:
p3 x p-2 = px
Solve for x:
22x + 2x +2 - 4 x 23 = 0
Find the value of k in each of the following:
`(sqrt(9))^-7 xx (sqrt(3))^-5` = 3k
Find the value of k in each of the following:
`(1/3)^-4 ÷ 9^((-1)/(3)` = 3k
If `x^(1/3) + y^(1/3) + z^(1/3) = 0`, prove that (x + y + z)3 = 27xyz
If 2x = 3y = 12z ; show that `(1)/z = (1)/y + (2)/x`.
