Advertisements
Advertisements
Question
Find the sum of a2 − ab + bc, 2ab + bc − 2a2 and − 3bc + 3a2 + ab.
Advertisements
Solution
(a2 − ab + bc) + (2ab + bc − 2a2) + (− 3bc + 3a2 + ab)
= a2 − ab + bc + 2ab + bc − 2a2 − 3bc + 3a2 + ab
= a2 + 3a2 − 2a2 + 2ab + ab − ab + bc + bc − 3bc
= 4a2 − 2a2 + 3ab − ab + 2bc − 3bc
= 2a2 + 2ab − bc
APPEARS IN
RELATED QUESTIONS
Find the sum of 4x2 + 7 − 3x, 4x − x2 + 8 and − 10 + 5x − 2x2.
Add the following expression:
− x2 − 3xy + 3y2 + 8, 3x2 − 5y2 − 3 + 4xy and − 6xy + 2x2 − 2 + y2
Evaluate:
(5x − 3y) − (x + y)
Evaluate:
7 − (4a − 5)
Take `(-3)/2"p"+"q"-"r"` from `1/2"p"-1/3"q"-3/2"r".`
From the sum of 3a – 2b + 4c and 3b – 2c subtract a – b – c.
By how much should x + 2y – 3z be increased to get 3x?
Fill in the blank:
− 4x × 5xy × 3z = ....................
The exponent form of t × t × t × t is:
The exponent form of a × a × b × b × b is:
