Advertisements
Advertisements
Question
Find the sum of 4x2 + 7 − 3x, 4x − x2 + 8 and − 10 + 5x − 2x2.
Advertisements
Solution
(4x2 + 7 − 3x) + (4x − x2 + 8) + (− 10 + 5x − 2x2)
= 4x2 + 7 − 3x + 4x − x2 + 8 − 10 + 5x − 2x2
= 4x2 − x2 − 2x2 + 7 + 8 − 10 + 4x + 5x − 3x
= 4x2 − 3x2 + 15 − 10 + 9x − 3x
= x2 + 5 + 6x
APPEARS IN
RELATED QUESTIONS
Subtract the first term from the second:
4.8b, 6.8b
Find the sum of x2 − x + 1, − 5x2 + 2x − 2 and 3x2 − 3x + 1
Subtract:
2ab + cd − ac − 2bd from ab − 2cd + 2ac + bd.
Take `(-3)/2"p"+"q"-"r"` from `1/2"p"-1/3"q"-3/2"r".`
From the sum of 3a – 2b + 4c and 3b – 2c subtract a – b – c.
Subtract x – 2y – z from the sum of 3x – y + z and x + y – 3z.
Subtract the sum of x + y and x – z from the sum of x – 2z and x + y + z
Fill in the blank:
− 5 × − 3x × 5x2 = ..................
Fill in the blank:
− 4x × 5xy × 3z = ....................
The value of y1 is:
