Advertisements
Advertisements
Question
Find the sum of 3x + 4xy − y2, xy − 4x + 2y2 and 3y2 − xy + 6x.
Advertisements
Solution
(3x + 4xy − y2) + (xy − 4x + 2y2) + (3y2 − xy + 6x)
= 3x + 4xy − y2 + xy − 4x + 2y2 + 3y2 − xy + 6x
= 3x + 6x − 4x + 4xy + xy − xy + 2y2 + 3y2 − y2
= 9x − 4x + 5xy − xy + 5y2 − y2
= 5x + 4xy + 4y2
APPEARS IN
RELATED QUESTIONS
Subtract the first term from the second:
3.5abc, 10.5abc
Add the following expression:
− x2 − 3xy + 3y2 + 8, 3x2 − 5y2 − 3 + 4xy and − 6xy + 2x2 − 2 + y2
Subtract:
5a − 3b + 2c from a − 4b − 2c.
From the sum of 3a – 2b + 4c and 3b – 2c subtract a – b – c.
Subtract x – 2y – z from the sum of 3x – y + z and x + y – 3z.
By how much should x + 2y – 3z be increased to get 3x?
Fill in the blank:
− 5 × − 3x × 5x2 = ..................
Fill in the blank:
8 × − 4xy2 × 3x3y2 = .............
The exponent form of a × a × b × b × b is:
The value of y1 is:
