Advertisements
Advertisements
प्रश्न
Find the sum of 3x + 4xy − y2, xy − 4x + 2y2 and 3y2 − xy + 6x.
योग
Advertisements
उत्तर
(3x + 4xy − y2) + (xy − 4x + 2y2) + (3y2 − xy + 6x)
= 3x + 4xy − y2 + xy − 4x + 2y2 + 3y2 − xy + 6x
= 3x + 6x − 4x + 4xy + xy − xy + 2y2 + 3y2 − y2
= 9x − 4x + 5xy − xy + 5y2 − y2
= 5x + 4xy + 4y2
shaalaa.com
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
APPEARS IN
संबंधित प्रश्न
Evaluate:
(8a + 15b) − (3b − 7a)
Evaluate:
(8x + 7y) − (4y − 3x)
Evaluate:
(6y − 13) − (4 − 7y)
Subtract:
− 8x − 12y + 17z from x − y − z.
Take 1 − a + a2 from a2 + a + 1.
From the sum of 3a – 2b + 4c and 3b – 2c subtract a – b – c.
Fill in the blanks:
6 × 3 = .............. and 6x2 × 3x3 = ............
Fill in the blank:
− 5 × − 3x × 5x2 = ..................
Fill in the blank:
5x × 2x2y × (− 7y3) × 2x3y2 = ...............
The exponent form of a × a × b × b × b is:
