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प्रश्न
Find the sum of 3x + 4xy − y2, xy − 4x + 2y2 and 3y2 − xy + 6x.
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उत्तर
(3x + 4xy − y2) + (xy − 4x + 2y2) + (3y2 − xy + 6x)
= 3x + 4xy − y2 + xy − 4x + 2y2 + 3y2 − xy + 6x
= 3x + 6x − 4x + 4xy + xy − xy + 2y2 + 3y2 − y2
= 9x − 4x + 5xy − xy + 5y2 − y2
= 5x + 4xy + 4y2
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संबंधित प्रश्न
Find the sum of x2 − x + 1, − 5x2 + 2x − 2 and 3x2 − 3x + 1
Add the following expression:
− x2 − 3xy + 3y2 + 8, 3x2 − 5y2 − 3 + 4xy and − 6xy + 2x2 − 2 + y2
Add the following expression:
a3 − 2b3 + a, b3 − 2a3 + b and − 2b + 2b3 − 5a + 4a3
Evaluate:
(8x + 7y) − (4y − 3x)
Subtract:
5a − 3b + 2c from a − 4b − 2c.
Subtract:
2ab + cd − ac − 2bd from ab − 2cd + 2ac + bd.
Take 1 − a + a2 from a2 + a + 1.
The sum of two expressions is 3a2 + 2ab – b2. If one of them is 2a2 + 3b2, find the other.
Fill in the blanks:
4 × 7 = .............. and 4ax × 7x = ............
Fill in the blank:
8 × − 4xy2 × 3x3y2 = .............
