Advertisements
Advertisements
प्रश्न
Find the sum of 4x2 + 7 − 3x, 4x − x2 + 8 and − 10 + 5x − 2x2.
Advertisements
उत्तर
(4x2 + 7 − 3x) + (4x − x2 + 8) + (− 10 + 5x − 2x2)
= 4x2 + 7 − 3x + 4x − x2 + 8 − 10 + 5x − 2x2
= 4x2 − x2 − 2x2 + 7 + 8 − 10 + 4x + 5x − 3x
= 4x2 − 3x2 + 15 − 10 + 9x − 3x
= x2 + 5 + 6x
APPEARS IN
संबंधित प्रश्न
Subtract the first term from the second:
3.5abc, 10.5abc
Find the sum of x2 − x + 1, − 5x2 + 2x − 2 and 3x2 − 3x + 1
Add the following expression:
a3 − 2b3 + a, b3 − 2a3 + b and − 2b + 2b3 − 5a + 4a3
Take − ab + bc − ca from bc − ca + ab.
From the sum of 3a – 2b + 4c and 3b – 2c subtract a – b – c.
Subtract the sum of x + y and x – z from the sum of x – 2z and x + y + z
Fill in the blanks:
5 × 4 = .............. and 5x × 4y = ............
Fill in the blanks:
1 × 8 = .............. and a2xy2 × 8a3x2y = ............
The exponent form of t × t × t × t is:
The value of y0 is:
