Advertisements
Advertisements
प्रश्न
Find the sum of a2 − ab + bc, 2ab + bc − 2a2 and − 3bc + 3a2 + ab.
Advertisements
उत्तर
(a2 − ab + bc) + (2ab + bc − 2a2) + (− 3bc + 3a2 + ab)
= a2 − ab + bc + 2ab + bc − 2a2 − 3bc + 3a2 + ab
= a2 + 3a2 − 2a2 + 2ab + ab − ab + bc + bc − 3bc
= 4a2 − 2a2 + 3ab − ab + 2bc − 3bc
= 2a2 + 2ab − bc
APPEARS IN
संबंधित प्रश्न
Subtract the first term from the second:
3.5abc, 10.5abc
Find the sum of 3x + 4xy − y2, xy − 4x + 2y2 and 3y2 − xy + 6x.
Subtract:
4x − 6y + 3z from 12x + 7y − 21z.
Subtract:
5 − a − 4b + 4c from 5a − 7b + 2c.
Subtract:
− 8x − 12y + 17z from x − y − z.
Subtract:
2ab + cd − ac − 2bd from ab − 2cd + 2ac + bd.
Take − ab + bc − ca from bc − ca + ab.
Take `(-3)/2"p"+"q"-"r"` from `1/2"p"-1/3"q"-3/2"r".`
The sum of two expressions is 5x2 – 3y2. If one of them is 3x2 + 4xy – y2, find the other.
Fill in the blanks:
6 × 3 = .............. and 6x × 3x = ............
