Advertisements
Advertisements
प्रश्न
Find the sum of a2 − ab + bc, 2ab + bc − 2a2 and − 3bc + 3a2 + ab.
Advertisements
उत्तर
(a2 − ab + bc) + (2ab + bc − 2a2) + (− 3bc + 3a2 + ab)
= a2 − ab + bc + 2ab + bc − 2a2 − 3bc + 3a2 + ab
= a2 + 3a2 − 2a2 + 2ab + ab − ab + bc + bc − 3bc
= 4a2 − 2a2 + 3ab − ab + 2bc − 3bc
= 2a2 + 2ab − bc
APPEARS IN
संबंधित प्रश्न
Add the following expression:
− 17x2 − 2xy + 23y2, − 9y2 + 15x2 + 7xy and 13x2 + 3y2 − 4xy
Add the following expression:
a3 − 2b3 + a, b3 − 2a3 + b and − 2b + 2b3 − 5a + 4a3
Subtract:
− 8x − 12y + 17z from x − y − z.
Take − ab + bc − ca from bc − ca + ab.
Take 1 − a + a2 from a2 + a + 1.
Subtract x – 2y – z from the sum of 3x – y + z and x + y – 3z.
Subtract the sum of x + y and x – z from the sum of x – 2z and x + y + z
The sum of two expressions is 3a2 + 2ab – b2. If one of them is 2a2 + 3b2, find the other.
Fill in the blanks:
4 × 7 = .............. and 4ax × 7x = ............
Fill in the blank:
3ab × 6ax = ..................
