Advertisements
Advertisements
प्रश्न
The sum of two expressions is 3a2 + 2ab – b2. If one of them is 2a2 + 3b2, find the other.
Advertisements
उत्तर
(3a2 + 2ab − b2) − (2a2 + 3b2)
= 3a2 + 2ab − b2 − 2a2 − 3b2
= 3a2 − 2a2 + 2ab − b2 − 3b2
= a2 + 2ab − 4b2
APPEARS IN
संबंधित प्रश्न
Subtract the first term from the second:
4ab, 6ba
Add the following expression:
− 17x2 − 2xy + 23y2, − 9y2 + 15x2 + 7xy and 13x2 + 3y2 − 4xy
Subtract:
5a − 3b + 2c from a − 4b − 2c.
Subtract:
− 8x − 12y + 17z from x − y − z.
Take `(-3)/2"p"+"q"-"r"` from `1/2"p"-1/3"q"-3/2"r".`
From the sum of x + y – 2z and 2x – y + z subtract x + y + z.
The sum of two expressions is 5x2 – 3y2. If one of them is 3x2 + 4xy – y2, find the other.
Fill in the blanks:
12 × 4 = .............. and 12ax2 × 4ax = ............
Fill in the blanks:
15 × 3 = .............. and 15x × 3x5y2 = ............
Fill in the blank:
6 × 6x2 × 6x2y2 = ...................
