Advertisements
Advertisements
प्रश्न
Take `(-3)/2"p"+"q"-"r"` from `1/2"p"-1/3"q"-3/2"r".`
Advertisements
उत्तर
`(1/2"p"-1/3"q"-3/2"r")-(-3/2"p"+"q"-"r")`
= `1/2"p"-1/3"q"-3/2"r"+3/2"p"-"q"+"r"`
= `1/2"p"+3/2"p"-1/3"q"-"q"-3/2"r"+"r"`
= `(3"p"+9"p"-2"q"-6"q"-9"r"+6"r")/6` ..........[Since L.C.M. = 6]
= `(12"p")/6-(8"q")/6-(3"r")/6`
= `2"p"-4/3"q"-1/2"r"`
APPEARS IN
संबंधित प्रश्न
Find the sum of 3a + 4b + 7c, − 5a + 3b − 6c and 4a − 2b − 4c.
Add the following expression:
− 17x2 − 2xy + 23y2, − 9y2 + 15x2 + 7xy and 13x2 + 3y2 − 4xy
Subtract:
− 8x − 12y + 17z from x − y − z.
Subtract the sum of x + y and x – z from the sum of x – 2z and x + y + z
By how much should x + 2y – 3z be increased to get 3x?
Fill in the blanks:
12 × 4 = .............. and 12ax2 × 4ax = ............
Fill in the blank:
4x × 6x × 2 = .....................
Fill in the blank:
5 × 5a3 = ................
Fill in the blank:
− 4x × 5xy × 3z = ....................
Fill in the blank:
5x × 2x2y × (− 7y3) × 2x3y2 = ...............
