Advertisements
Advertisements
प्रश्न
Take `(-3)/2"p"+"q"-"r"` from `1/2"p"-1/3"q"-3/2"r".`
Advertisements
उत्तर
`(1/2"p"-1/3"q"-3/2"r")-(-3/2"p"+"q"-"r")`
= `1/2"p"-1/3"q"-3/2"r"+3/2"p"-"q"+"r"`
= `1/2"p"+3/2"p"-1/3"q"-"q"-3/2"r"+"r"`
= `(3"p"+9"p"-2"q"-6"q"-9"r"+6"r")/6` ..........[Since L.C.M. = 6]
= `(12"p")/6-(8"q")/6-(3"r")/6`
= `2"p"-4/3"q"-1/2"r"`
APPEARS IN
संबंधित प्रश्न
Subtract the first term from the second:
3.5abc, 10.5abc
Find the sum of 3a + 4b + 7c, − 5a + 3b − 6c and 4a − 2b − 4c.
Find the sum of a2 − ab + bc, 2ab + bc − 2a2 and − 3bc + 3a2 + ab.
Find the sum of 4x2 + 7 − 3x, 4x − x2 + 8 and − 10 + 5x − 2x2.
By how much should x + 2y – 3z be increased to get 3x?
The sum of two expressions is 3a2 + 2ab – b2. If one of them is 2a2 + 3b2, find the other.
Fill in the blanks:
5 × 4 = .............. and 5x × 4y = ............
Fill in the blank:
5 × 5a3 = ................
Fill in the blank:
− 8x × − 3x = − ....................
The value of y1 is:
