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प्रश्न
Find the sum of 3a + 4b + 7c, − 5a + 3b − 6c and 4a − 2b − 4c.
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उत्तर
(3a + 4b + 7c) + (− 5a + 3b − 6c) + (4a − 2b − 4c)
= 3a + 4b + 7c − 5a + 3b − 6c + 4a − 2b − 4c
= 3a + 4a − 5a + 4b + 3b − 2b + 7c − 6c − 4c
= 7a − 5a + 7b − 2b + 7c − 10c
= 2a + 5b − 3c
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संबंधित प्रश्न
Subtract the first term from the second:
3.5abc, 10.5abc
Subtract the first term from the second:
`3 1/2"mn",8 1/2"nm"`
Add the following expression:
− x2 − 3xy + 3y2 + 8, 3x2 − 5y2 − 3 + 4xy and − 6xy + 2x2 − 2 + y2
Add the following expression:
a3 − 2b3 + a, b3 − 2a3 + b and − 2b + 2b3 − 5a + 4a3
Subtract:
5 − a − 4b + 4c from 5a − 7b + 2c.
Take 5x + 6y − 3z from 3x + 5y − 4z.
Take 1 − a + a2 from a2 + a + 1.
From the sum of 3a – 2b + 4c and 3b – 2c subtract a – b – c.
Fill in the blanks:
1 × 8 = .............. and a2xy2 × 8a3x2y = ............
The value of y0 is:
