Advertisements
Advertisements
Question
Take `(-3)/2"p"+"q"-"r"` from `1/2"p"-1/3"q"-3/2"r".`
Advertisements
Solution
`(1/2"p"-1/3"q"-3/2"r")-(-3/2"p"+"q"-"r")`
= `1/2"p"-1/3"q"-3/2"r"+3/2"p"-"q"+"r"`
= `1/2"p"+3/2"p"-1/3"q"-"q"-3/2"r"+"r"`
= `(3"p"+9"p"-2"q"-6"q"-9"r"+6"r")/6` ..........[Since L.C.M. = 6]
= `(12"p")/6-(8"q")/6-(3"r")/6`
= `2"p"-4/3"q"-1/2"r"`
APPEARS IN
RELATED QUESTIONS
Subtract the first term from the second:
4ab, 6ba
Evaluate:
3a − (a + 2b)
From the sum of 3a – 2b + 4c and 3b – 2c subtract a – b – c.
Subtract the sum of x + y and x – z from the sum of x – 2z and x + y + z
Fill in the blanks:
6 × 3 = .............. and 6x × 3x = ............
Fill in the blanks:
4 × 7 = .............. and 4ax × 7x = ............
Fill in the blanks:
6 × 2 = .............. and 6xy × 2xy = ............
Fill in the blanks:
1 × 8 = .............. and a2xy2 × 8a3x2y = ............
Fill in the blank:
− 5 × − 3x × 5x2 = ..................
The value of y1 is:
