Advertisements
Advertisements
Question
Take `(-3)/2"p"+"q"-"r"` from `1/2"p"-1/3"q"-3/2"r".`
Advertisements
Solution
`(1/2"p"-1/3"q"-3/2"r")-(-3/2"p"+"q"-"r")`
= `1/2"p"-1/3"q"-3/2"r"+3/2"p"-"q"+"r"`
= `1/2"p"+3/2"p"-1/3"q"-"q"-3/2"r"+"r"`
= `(3"p"+9"p"-2"q"-6"q"-9"r"+6"r")/6` ..........[Since L.C.M. = 6]
= `(12"p")/6-(8"q")/6-(3"r")/6`
= `2"p"-4/3"q"-1/2"r"`
APPEARS IN
RELATED QUESTIONS
Find the sum of 4x2 + 7 − 3x, 4x − x2 + 8 and − 10 + 5x − 2x2.
Add the following expression:
− 17x2 − 2xy + 23y2, − 9y2 + 15x2 + 7xy and 13x2 + 3y2 − 4xy
Add the following expression:
− x2 − 3xy + 3y2 + 8, 3x2 − 5y2 − 3 + 4xy and − 6xy + 2x2 − 2 + y2
Evaluate:
(8a + 15b) − (3b − 7a)
Subtract:
5a − 3b + 2c from a − 4b − 2c.
Subtract:
− 8x − 12y + 17z from x − y − z.
Take 1 − a + a2 from a2 + a + 1.
From the sum of x + y – 2z and 2x – y + z subtract x + y + z.
The exponent form of t × t × t × t is:
The value of y0 is:
