Advertisements
Advertisements
Question
Take `(-3)/2"p"+"q"-"r"` from `1/2"p"-1/3"q"-3/2"r".`
Advertisements
Solution
`(1/2"p"-1/3"q"-3/2"r")-(-3/2"p"+"q"-"r")`
= `1/2"p"-1/3"q"-3/2"r"+3/2"p"-"q"+"r"`
= `1/2"p"+3/2"p"-1/3"q"-"q"-3/2"r"+"r"`
= `(3"p"+9"p"-2"q"-6"q"-9"r"+6"r")/6` ..........[Since L.C.M. = 6]
= `(12"p")/6-(8"q")/6-(3"r")/6`
= `2"p"-4/3"q"-1/2"r"`
APPEARS IN
RELATED QUESTIONS
Subtract the first term from the second:
4ab, 6ba
Find the sum of 2x2 + xy − y2, − x2 + 2xy + 3y2 and 3x2 − 10xy + 4y2.
Add the following expression:
a3 − 2b3 + a, b3 − 2a3 + b and − 2b + 2b3 − 5a + 4a3
Evaluate:
(6y − 13) − (4 − 7y)
Subtract:
5a − 3b + 2c from a − 4b − 2c.
Subtract:
4x − 6y + 3z from 12x + 7y − 21z.
Take 1 − a + a2 from a2 + a + 1.
The sum of two expressions is 5x2 – 3y2. If one of them is 3x2 + 4xy – y2, find the other.
Fill in the blanks:
6 × 3 = .............. and 6x2 × 3x3 = ............
Fill in the blank:
− 5 × − 3x × 5x2 = ..................
