Advertisements
Advertisements
प्रश्न
Subtract:
2ab + cd − ac − 2bd from ab − 2cd + 2ac + bd.
Advertisements
उत्तर
(ab − 2cd + 2ac + bd) − (2ab + cd − ac − 2bd)
= ab − 2cd + 2ac + bd − 2ab − cd + ac + 2bd
= ab − 2ab − 2cd − cd + 2ac + ac + bd + 2bd
= − ab − 3cd + 3ac + 3bd
APPEARS IN
संबंधित प्रश्न
Find the sum of 2x2 + xy − y2, − x2 + 2xy + 3y2 and 3x2 − 10xy + 4y2.
Find the sum of a2 − ab + bc, 2ab + bc − 2a2 and − 3bc + 3a2 + ab.
Find the sum of 4x2 + 7 − 3x, 4x − x2 + 8 and − 10 + 5x − 2x2.
Add the following expression:
− 17x2 − 2xy + 23y2, − 9y2 + 15x2 + 7xy and 13x2 + 3y2 − 4xy
Evaluate:
(6y − 13) − (4 − 7y)
Subtract x – 2y – z from the sum of 3x – y + z and x + y – 3z.
Fill in the blanks:
1 × 8 = .............. and a2xy2 × 8a3x2y = ............
Fill in the blank:
− 8x × − 3x = − ....................
Fill in the blank:
− 5 × − 3x × 5x2 = ..................
Fill in the blank:
5x × 2x2y × (− 7y3) × 2x3y2 = ...............
