Advertisements
Advertisements
Question
Add the following expression:
− x2 − 3xy + 3y2 + 8, 3x2 − 5y2 − 3 + 4xy and − 6xy + 2x2 − 2 + y2
Advertisements
Solution
(− x2 − 3xy + 3y2 + 8) + (3x2 − 5y2 − 3 + 4xy) + (− 6xy + 2x2 − 2 + y2)
= − x2 − 3xy + 3y2 + 8 + 3x2 − 5y2 − 3 + 4xy − 6xy + 2x2 − 2 + y2
= − x2 + 3x2 + 2x2 − 3xy − 6xy + 4xy + 3y2 + y2 − 5y2 + 8 − 3 − 2
= 4x2 − 5xy − y2 + 3
APPEARS IN
RELATED QUESTIONS
Subtract the first term from the second:
4ab, 6ba
Subtract the first term from the second:
`3 1/2"mn",8 1/2"nm"`
Subtract:
5a − 3b + 2c from a − 4b − 2c.
Take `(-3)/2"p"+"q"-"r"` from `1/2"p"-1/3"q"-3/2"r".`
Subtract x – 2y – z from the sum of 3x – y + z and x + y – 3z.
By how much should x + 2y – 3z be increased to get 3x?
The sum of two expressions is 3a2 + 2ab – b2. If one of them is 2a2 + 3b2, find the other.
Fill in the blanks:
1 × 8 = .............. and a2xy2 × 8a3x2y = ............
Fill in the blank:
5 × 5a3 = ................
Fill in the blank:
− 8x × − 3x = − ....................
