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Question
Find the sum of 2x2 + xy − y2, − x2 + 2xy + 3y2 and 3x2 − 10xy + 4y2.
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Solution
(2x2 + xy − y2) + (− x2 + 2xy + 3y2) + (3x2 − 10xy + 4y2)
= 2x2 + xy − y2 − x2 + 2xy + 3y2 + 3x2 − 10xy + 4y2
= 2x2 + 3x2 − x2 + xy + 2xy − 10xy + 3y2 + 4y2 − y2
= 5x2 − x2 + 3xy − 10xy + 7y2 − y2
= 4x2 − 7xy + 6y2
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