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प्रश्न
Find the sum of 2x2 + xy − y2, − x2 + 2xy + 3y2 and 3x2 − 10xy + 4y2.
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उत्तर
(2x2 + xy − y2) + (− x2 + 2xy + 3y2) + (3x2 − 10xy + 4y2)
= 2x2 + xy − y2 − x2 + 2xy + 3y2 + 3x2 − 10xy + 4y2
= 2x2 + 3x2 − x2 + xy + 2xy − 10xy + 3y2 + 4y2 − y2
= 5x2 − x2 + 3xy − 10xy + 7y2 − y2
= 4x2 − 7xy + 6y2
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संबंधित प्रश्न
Subtract the first term from the second:
4ab, 6ba
Subtract the first term from the second:
3.5abc, 10.5abc
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Add the following expression:
− x2 − 3xy + 3y2 + 8, 3x2 − 5y2 − 3 + 4xy and − 6xy + 2x2 − 2 + y2
Evaluate:
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Subtract:
5a − 3b + 2c from a − 4b − 2c.
Fill in the blanks:
1 × 8 = .............. and a2xy2 × 8a3x2y = ............
Fill in the blank:
5 × 5a3 = ................
Fill in the blank:
− 8x × − 3x = − ....................
The value of y1 is:
