Advertisements
Advertisements
Question
Find the perimeter of the rectangle whose length is 40 cm and a diagonal is 41 cm.
Advertisements
Solution
Length of rectangle = 40 cm, Diagonal = 41 cm
Let the breadth of rectangle = x cm

From right angled triangle ΔABC,
AC2 = AB2 + BC2
(41)2 = (40)2 + BC2
BC2 = 1681 – 1600
BC2 = 81
BC = 9
Perimeter of rectangle = 2 (40 + 9)
= 2 × 49
= 98 cm
Hence, perimeter of rectangle = 98 cm
APPEARS IN
RELATED QUESTIONS
ABC is a right triangle right-angled at C. Let BC = a, CA = b, AB = c and let p be the length of perpendicular from C on AB, prove that
(i) cp = ab
`(ii) 1/p^2=1/a^2+1/b^2`
In Figure, ABD is a triangle right angled at A and AC ⊥ BD. Show that AB2 = BC × BD

In the following figure, O is a point in the interior of a triangle ABC, OD ⊥ BC, OE ⊥ AC and OF ⊥ AB. Show that

(i) OA2 + OB2 + OC2 − OD2 − OE2 − OF2 = AF2 + BD2 + CE2
(ii) AF2 + BD2 + CE2 = AE2 + CD2 + BF2
PQR is a triangle right angled at P. If PQ = 10 cm and PR = 24 cm, find QR.
Choose the correct alternative:
In right-angled triangle PQR, if hypotenuse PR = 12 and PQ = 6, then what is the measure of ∠P?
In the given figure, angle ACP = ∠BDP = 90°, AC = 12 m, BD = 9 m and PA= PB = 15 m. Find:
(i) CP
(ii) PD
(iii) CD

The length of the diagonals of rhombus are 24cm and 10cm. Find each side of the rhombus.
The top of a broken tree touches the ground at a distance of 12 m from its base. If the tree is broken at a height of 5 m from the ground then the actual height of the tree is ______.
Points A and B are on the opposite edges of a pond as shown in the following figure. To find the distance between the two points, the surveyor makes a right-angled triangle as shown. Find the distance AB.

Two poles of 10 m and 15 m stand upright on a plane ground. If the distance between the tops is 13 m, find the distance between their feet.
