Advertisements
Advertisements
प्रश्न
Find the perimeter of the rectangle whose length is 40 cm and a diagonal is 41 cm.
Advertisements
उत्तर
Length of rectangle = 40 cm, Diagonal = 41 cm
Let the breadth of rectangle = x cm

From right angled triangle ΔABC,
AC2 = AB2 + BC2
(41)2 = (40)2 + BC2
BC2 = 1681 – 1600
BC2 = 81
BC = 9
Perimeter of rectangle = 2 (40 + 9)
= 2 × 49
= 98 cm
Hence, perimeter of rectangle = 98 cm
APPEARS IN
संबंधित प्रश्न
A ladder leaning against a wall makes an angle of 60° with the horizontal. If the foot of the ladder is 2.5 m away from the wall, find the length of the ladder
In figure, ∠B of ∆ABC is an acute angle and AD ⊥ BC, prove that AC2 = AB2 + BC2 – 2BC × BD
In a trapezium ABCD, seg AB || seg DC seg BD ⊥ seg AD, seg AC ⊥ seg BC, If AD = 15, BC = 15 and AB = 25. Find A(▢ABCD)

In a quadrilateral ABCD, ∠B = 90° and ∠D = 90°.
Prove that: 2AC2 - AB2 = BC2 + CD2 + DA2
Find the Pythagorean triplet from among the following set of numbers.
3, 4, 5
If ‘l‘ and ‘m’ are the legs and ‘n’ is the hypotenuse of a right angled triangle then, l2 = ________
In a right angled triangle, the hypotenuse is the greatest side
If length of sides of a triangle are a, b, c and a2 + b2 = c2, then which type of triangle it is?
In a right-angled triangle ABC, if angle B = 90°, then which of the following is true?
The hypotenuse (in cm) of a right angled triangle is 6 cm more than twice the length of the shortest side. If the length of third side is 6 cm less than thrice the length of shortest side, then find the dimensions of the triangle.
