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Maharashtra State BoardSSC (English Medium) 7th Standard

In the right-angled ∆PQR, ∠ P = 90°. If l(PQ) = 24 cm and l(PR) = 10 cm, find the length of seg QR. - Mathematics

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Question

In the right-angled ∆PQR, ∠ P = 90°. If l(PQ) = 24 cm and l(PR) = 10 cm, find the length of seg QR.

Sum
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Solution

In the right-angled triangle PQR, ∠P = 90°. Hence, side QR is the hypotenuse.
According to Pythagoras' theorem,

l(QR)2 = l(PQ)2 + l(PR)2

⇒ l(QR)2 = (24)2 + (10)2

⇒ l(QR)2 = 576 + 100

⇒ l(QR)2 = 676

⇒ l(QR)2 = (26)2

⇒ l(QR) = 26

∴ Length of seg QR = 26 cm.

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Chapter 13: Pythagoras’ Theorem - Practice Set 48 [Page 90]

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Balbharati Mathematics [English] Standard 7 Maharashtra State Board
Chapter 13 Pythagoras’ Theorem
Practice Set 48 | Q 2 | Page 90
Balbharati Mathematics Integrated [English] Standard 7 Maharashtra State Board
Chapter 13 Pythagoras' Theorem
Practice Set 48 | Q 2. | Page 40

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