Advertisements
Advertisements
Question
Find the area of an isosceles triangle whose base is 16 cm and the length of each of the equal sides is 10 cm.
Advertisements
Solution
In isosceles Δ ABC
Base BC = 16 cm
and AB = AC = 10 cm
Let AD ⊥ BC and BD = `1/2"BC"=16/2`
∴ BD = 8 cm
In right Δ ABD
AB2 = AD2 + BD2 ..............(Pythagoras Theorem)
(10)2 = AD2 + (8)2
100 = AD2 + 64
100 − 64 = AD2
36 = AD2
AD = `sqrt36=sqrt(6xx6)`
∴ AD = 6 cm
Now, the area of triangle =`("Base"xx"Altitude")/2`
= `(16xx6)/2` = 48 cm2
APPEARS IN
RELATED QUESTIONS
Find the area of the square whose perimeter is 56 cm.
In the figure given below, find the area of shaded region: (All measurements are in cm)
In the figure given below, find the area of shaded region: (All measurements are in cm)
Find the area of a triangle whose base is 30 cm and the height is 18 cm.
Find the height of a triangle whose base is 18 cm and the area is 270 cm2.
The area of a right-angled triangle is 160 cm2. If its one leg is 16 cm long, find the length of the other leg.
Find the area of a right-angled triangle whose hypotenuse is 13 cm long and one of its legs is 12 cm long.
The sides of a triangle are 21 cm, 17 cm, and 10 cm. Find its area.
The area of an equilateral triangle is (`64xxsqrt3`) cm2. Find the length of each side of the triangle.
The length and breadth of a rectangular paper are 35 cm and 22 cm. Find the area of the largest circle which can be cut out of this paper.
