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Question
The adjacent sides of a parallelogram are 15 cm and 10 cm. If the distance between the longer sides is 6 cm, find the distance between the shorter sides.
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Solution
In parallelogram ABCD
AB = DC = 15 cm
BC = AD = 10 cm
Distance between longer sides AB and DC is 6 cm
i.e., perpendicular DL = 6 cm
DM ⊥ BC
Area of parallelogram = Base × Altitude
= AB × DL = 15 × 6 = 90 cm2
Again let DM = x cm
∴ Area of parallelogram ABCD = BC × DM
= 10 × x = 10x cm2
∴ 10x cm2 = 90 cm2
⇒ x = `90/10` = 9 cm
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