Advertisements
Advertisements
Question
The adjacent sides of a parallelogram are 15 cm and 10 cm. If the distance between the longer sides is 6 cm, find the distance between the shorter sides.
Advertisements
Solution
In parallelogram ABCD
AB = DC = 15 cm
BC = AD = 10 cm
Distance between longer sides AB and DC is 6 cm
i.e., perpendicular DL = 6 cm
DM ⊥ BC
Area of parallelogram = Base × Altitude
= AB × DL = 15 × 6 = 90 cm2
Again let DM = x cm
∴ Area of parallelogram ABCD = BC × DM
= 10 × x = 10x cm2
∴ 10x cm2 = 90 cm2
⇒ x = `90/10` = 9 cm
APPEARS IN
RELATED QUESTIONS
A square lawn is surrounded by a path 2.5 m wide. If the area of the path is 165 m2 find the area of the lawn.
One side of a parallelogram is 20 cm and its distance from the opposite side is 16 cm. Find the area of the parallelogram.
Find the area of the rhombus, if its diagonals are 30 cm and 24 cm.
One side of a parallelogram is 18 cm and its area is 153 cm2. Find the distance of the given side from its opposite side.
The area of a rhombus is 84 cm2 and its perimeter is 56 cm. Find its height.
Find the area of a triangle whose base is 30 cm and the height is 18 cm.
Find the height of a triangle whose base is 18 cm and the area is 270 cm2.
Find the area of a right-angled triangle whose hypotenuse is 13 cm long and one of its legs is 12 cm long.
The diameter of every wheel of a car is 63 cm. How much distance will the car move during the 2000 revolutions of its wheel.
A wire is along the boundary of a circle with a radius of 28 cm. If the same wire is bent in the form of a square, find the area of the square formed.
