Question

The adjacent sides of a parallelogram are 15 cm and 10 cm. If the distance between the longer sides is 6 cm, find the distance between the shorter sides.

Answer 1

In parallelogram ABCD

AB = DC = 15 cm

BC = AD = 10 cm

Distance between longer sides AB and DC is 6 cm

i.e., perpendicular DL = 6 cm

DM ⊥ BC

Area of parallelogram = Base × Altitude

= AB × DL = 15 × 6 = 90 cm²

Again let DM = x cm

∴ Area of parallelogram ABCD = BC × DM 

= 10 × x = 10x cm²

∴ 10x cm² = 90 cm²

⇒ x = `90/10` = 9 cm