Advertisements
Advertisements
Question
The adjacent sides of a parallelogram are 15 cm and 10 cm. If the distance between the longer sides is 6 cm, find the distance between the shorter sides.
Advertisements
Solution
In parallelogram ABCD
AB = DC = 15 cm
BC = AD = 10 cm
Distance between longer sides AB and DC is 6 cm
i.e., perpendicular DL = 6 cm
DM ⊥ BC
Area of parallelogram = Base × Altitude
= AB × DL = 15 × 6 = 90 cm2
Again let DM = x cm
∴ Area of parallelogram ABCD = BC × DM
= 10 × x = 10x cm2
∴ 10x cm2 = 90 cm2
⇒ x = `90/10` = 9 cm
APPEARS IN
RELATED QUESTIONS
In the figure given below, find the area of shaded region: (All measurements are in cm)
In the figure given below, find the area of shaded region: (All measurements are in cm)
The base of a parallelogram is thrice it height. If its area is 768 cm2, find the base and the height of the parallelogram.
One side of a parallelogram is 18 cm and its area is 153 cm2. Find the distance of the given side from its opposite side.
Find the area of a right-angled triangle whose hypotenuse is 13 cm long and one of its legs is 12 cm long.
Find the base of a triangle whose area is 360 cm2 and height is 24 cm.
The legs of a right-angled triangle are in the ratio 4 : 3 and its area is 4056 cm2. Find the length of its legs.
The ratio between the areas of two circles is 16 : 9. Find the ratio between their :
(i) radius
(ii) diameters
(iii) circumference
The diameter of the wheel of a car is 70 cm. How many revolutions will it make to travel one kilometer?
A wire is along the boundary of a circle with a radius of 28 cm. If the same wire is bent in the form of a square, find the area of the square formed.
