Advertisements
Advertisements
प्रश्न
The adjacent sides of a parallelogram are 15 cm and 10 cm. If the distance between the longer sides is 6 cm, find the distance between the shorter sides.
Advertisements
उत्तर
In parallelogram ABCD
AB = DC = 15 cm
BC = AD = 10 cm
Distance between longer sides AB and DC is 6 cm
i.e., perpendicular DL = 6 cm
DM ⊥ BC
Area of parallelogram = Base × Altitude
= AB × DL = 15 × 6 = 90 cm2
Again let DM = x cm
∴ Area of parallelogram ABCD = BC × DM
= 10 × x = 10x cm2
∴ 10x cm2 = 90 cm2
⇒ x = `90/10` = 9 cm
APPEARS IN
संबंधित प्रश्न
Find the area of the square whose perimeter is 56 cm.
In the figure given below, find the area of shaded region: (All measurements are in cm)
In the figure given below, find the area of shaded region: (All measurements are in cm)
The base of a parallelogram is thrice it height. If its area is 768 cm2, find the base and the height of the parallelogram.
If the area of a rhombus is 112 cm2 and one of its diagonals is 14 cm, find its other diagonal.
The area of a rhombus is 84 cm2 and its perimeter is 56 cm. Find its height.
Find the area of a triangle whose base is 30 cm and the height is 18 cm.
Find the area of a right-angled triangle whose hypotenuse is 13 cm long and one of its legs is 12 cm long.
Find the area of an equilateral triangle whose each side is 16 cm. (Take `sqrt3`= 1.73)
From each corner of a rectangular paper (30 cm x 20 cm) a quadrant of a circle of radius 7 cm is cut. Find the area of the remaining paper i.e., shaded portion.
