Advertisements
Advertisements
प्रश्न
Find the area of a right-angled triangle whose hypotenuse is 13 cm long and one of its legs is 12 cm long.
Advertisements
उत्तर
In right-angled Δ ABC,
Base BC = 12 cm
and hypotenuse AC = 13 cm
Applying Pythagoras Theorem,
(AC)2 = (AB)2 + (BC)2
(13)2 = (AB)2 + (12)2
169 = (AB)2 + 144
(AB)2 = 169 − 144
(AB)2 = 25
∴ AB =`sqrt25`
= `sqrt(5xx5)` = 5 cm
Now, area of Δ ABC =`1/2"base"xx"altitude"`
= `1/2xx12xx5` = 30 cm2
APPEARS IN
संबंधित प्रश्न
Find the area of the square whose perimeter is 56 cm.
A square lawn is surrounded by a path 2.5 m wide. If the area of the path is 165 m2 find the area of the lawn.
In the figure given below, find the area of shaded region: (All measurements are in cm)
In the figure given below, find the area of shaded region: (All measurements are in cm)
Find the area of an isosceles triangle whose base is 16 cm and the length of each of the equal sides is 10 cm.
The sides of a triangle are in the ratio 15 : 13 : 14 and its perimeter is 168 cm. Find the area of the triangle.
The diameter of a circle is 20 cm. Taking π = 3.14, find the circumference and its area.
The ratio between the radius of two circles is 5 : 7. Find the ratio between their:
(i) circumference
(ii) areas
The diameter of the wheel of a car is 70 cm. How many revolutions will it make to travel one kilometer?
From each corner of a rectangular paper (30 cm x 20 cm) a quadrant of a circle of radius 7 cm is cut. Find the area of the remaining paper i.e., shaded portion.
