Advertisements
Advertisements
प्रश्न
Find the area of an isosceles triangle whose base is 16 cm and the length of each of the equal sides is 10 cm.
Advertisements
उत्तर
In isosceles Δ ABC
Base BC = 16 cm
and AB = AC = 10 cm
Let AD ⊥ BC and BD = `1/2"BC"=16/2`
∴ BD = 8 cm
In right Δ ABD
AB2 = AD2 + BD2 ..............(Pythagoras Theorem)
(10)2 = AD2 + (8)2
100 = AD2 + 64
100 − 64 = AD2
36 = AD2
AD = `sqrt36=sqrt(6xx6)`
∴ AD = 6 cm
Now, the area of triangle =`("Base"xx"Altitude")/2`
= `(16xx6)/2` = 48 cm2
APPEARS IN
संबंधित प्रश्न
In the figure given below, find the area of shaded region: (All measurements are in cm)
In the figure given below, find the area of shaded region: (All measurements are in cm)
One side of a parallelogram is 18 cm and its area is 153 cm2. Find the distance of the given side from its opposite side.
Find the area of a triangle whose base is 30 cm and the height is 18 cm.
The area of a right-angled triangle is 160 cm2. If its one leg is 16 cm long, find the length of the other leg.
Find the area of an equilateral triangle whose each side is 16 cm. (Take `sqrt3`= 1.73)
The sides of a triangle are 21 cm, 17 cm, and 10 cm. Find its area.
The ratio between the areas of two circles is 16 : 9. Find the ratio between their :
(i) radius
(ii) diameters
(iii) circumference
The diameter of every wheel of a car is 63 cm. How much distance will the car move during the 2000 revolutions of its wheel.
From each corner of a rectangular paper (30 cm x 20 cm) a quadrant of a circle of radius 7 cm is cut. Find the area of the remaining paper i.e., shaded portion.
