Advertisements
Advertisements
प्रश्न
Find the area of an isosceles triangle whose base is 16 cm and the length of each of the equal sides is 10 cm.
Advertisements
उत्तर
In isosceles Δ ABC
Base BC = 16 cm
and AB = AC = 10 cm
Let AD ⊥ BC and BD = `1/2"BC"=16/2`
∴ BD = 8 cm
In right Δ ABD
AB2 = AD2 + BD2 ..............(Pythagoras Theorem)
(10)2 = AD2 + (8)2
100 = AD2 + 64
100 − 64 = AD2
36 = AD2
AD = `sqrt36=sqrt(6xx6)`
∴ AD = 6 cm
Now, the area of triangle =`("Base"xx"Altitude")/2`
= `(16xx6)/2` = 48 cm2
APPEARS IN
संबंधित प्रश्न
Find the area of the rhombus, if its diagonals are 30 cm and 24 cm.
The area of a rhombus is 84 cm2 and its perimeter is 56 cm. Find its height.
Find the height of a triangle whose base is 18 cm and the area is 270 cm2.
The area of a right-angled triangle is 160 cm2. If its one leg is 16 cm long, find the length of the other leg.
The sides of a triangle are 21 cm, 17 cm, and 10 cm. Find its area.
The diameter of a circle is 20 cm. Taking π = 3.14, find the circumference and its area.
The ratio between the areas of two circles is 16 : 9. Find the ratio between their :
(i) radius
(ii) diameters
(iii) circumference
The diameter of the wheel of a car is 70 cm. How many revolutions will it make to travel one kilometer?
A wire is along the boundary of a circle with a radius of 28 cm. If the same wire is bent in the form of a square, find the area of the square formed.
From each corner of a rectangular paper (30 cm x 20 cm) a quadrant of a circle of radius 7 cm is cut. Find the area of the remaining paper i.e., shaded portion.
