Advertisements
Advertisements
प्रश्न
The sides of a triangle are 21 cm, 17 cm, and 10 cm. Find its area.
Advertisements
उत्तर
Let a = 21 cm, b = 17 cm and c = 10 cm
∴ a + b + c
= 21 cm + 17 cm + 10 cm = 48 cm
s =`"a + b + c"/2=48/2` = 24 cm
Area of the triangle
= `sqrt(s(s-a)(s-b)(s-c))`
= `sqrt(24(24-21)(24-17)(24-10))`
= `sqrt(24xx3xx7xx14)`
= `sqrt(2xx2xx2xx3xx3xx7xx2xx7)`
= 2 × 2 × 3 × 7
= 84 cm2
APPEARS IN
संबंधित प्रश्न
A square lawn is surrounded by a path 2.5 m wide. If the area of the path is 165 m2 find the area of the lawn.
In the figure given below, find the area of shaded region: (All measurements are in cm)
In the figure given below, find the area of shaded region: (All measurements are in cm)
One side of a parallelogram is 20 cm and its distance from the opposite side is 16 cm. Find the area of the parallelogram.
One side of a parallelogram is 18 cm and its area is 153 cm2. Find the distance of the given side from its opposite side.
The adjacent sides of a parallelogram are 15 cm and 10 cm. If the distance between the longer sides is 6 cm, find the distance between the shorter sides.
The area of a rhombus is 84 cm2 and its perimeter is 56 cm. Find its height.
Find the area of a right-angled triangle whose hypotenuse is 13 cm long and one of its legs is 12 cm long.
The area of an equilateral triangle is (`64xxsqrt3`) cm2. Find the length of each side of the triangle.
The length and breadth of a rectangular paper are 35 cm and 22 cm. Find the area of the largest circle which can be cut out of this paper.
