Advertisements
Advertisements
Question
Find the area of a right-angled triangle whose hypotenuse is 13 cm long and one of its legs is 12 cm long.
Advertisements
Solution
In right-angled Δ ABC,
Base BC = 12 cm
and hypotenuse AC = 13 cm
Applying Pythagoras Theorem,
(AC)2 = (AB)2 + (BC)2
(13)2 = (AB)2 + (12)2
169 = (AB)2 + 144
(AB)2 = 169 − 144
(AB)2 = 25
∴ AB =`sqrt25`
= `sqrt(5xx5)` = 5 cm
Now, area of Δ ABC =`1/2"base"xx"altitude"`
= `1/2xx12xx5` = 30 cm2
APPEARS IN
RELATED QUESTIONS
In the figure given below, find the area of shaded region: (All measurements are in cm)
In the figure given below, find the area of shaded region: (All measurements are in cm)
In the figure given below, find the area of shaded region: (All measurements are in cm)
In the figure given below, find the area of shaded region: (All measurements are in cm)
Find the area of a triangle whose base is 30 cm and the height is 18 cm.
Find the height of a triangle whose base is 18 cm and the area is 270 cm2.
Find the area of an equilateral triangle whose each side is 16 cm. (Take `sqrt3`= 1.73)
Find the area of an isosceles triangle whose base is 16 cm and the length of each of the equal sides is 10 cm.
The ratio between the radius of two circles is 5 : 7. Find the ratio between their:
(i) circumference
(ii) areas
A metal wire, when bent in the form of a square of largest area, encloses an area of 484 cm2. Find the length of the wire. If the same wire is bent to the largest circle, find:
(i) radius of the circle formed.
(ii) area of the circle.
