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Find the Equation of the Straight Line Which Passes Through the Point P (2, 6) and Cuts the Coordinate Axes at the Point a and B Respectively So that - Mathematics

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Question

Find the equation of the straight line which passes through the point P (2, 6) and cuts the coordinate axes at the point A and B respectively so that \[\frac{AP}{BP} = \frac{2}{3}\] .

Answer in Brief
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Solution

The equation of the line with intercepts a and b is \[\frac{x}{a} + \frac{y}{b} = 1\]

Since, the line meets the coordinate axes at A and B, the coordinates of A and B are A (a, 0) and B(0, b).
Given:

\[AP : BP = 2 : 3\]
Here, 
\[P \equiv \left( 2, 6 \right)\]

\[\therefore 2 = \frac{2 \times 0 + 3 \times a}{2 + 3}, 6 = \frac{2 \times b + 3 \times 0}{2 + 3}\]

\[ \Rightarrow 3a = 10, 2b = 30\]

\[ \Rightarrow a = \frac{10}{3}, b = 15\]

Thus, the equation of the line is

\[\frac{x}{\frac{10}{3}} + \frac{y}{15} = 1\]

\[ \Rightarrow \frac{3x}{10} + \frac{y}{15} = 1\]

\[ \Rightarrow 9x + 2y = 30\]

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Equations of Line in Different Forms - Equation of Family of Lines Passing Through the Point of Intersection of Two Lines
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Chapter 23: The straight lines - Exercise 23.6 [Page 47]

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RD Sharma Mathematics [English] Class 11
Chapter 23 The straight lines
Exercise 23.6 | Q 15 | Page 47

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