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Find the Equation of the Circle With: Centre (A, A) and Radius √ 2 A.

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Question

Find the equation of the circle with:

Centre (aa) and radius \[\sqrt{2}\]a.

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Solution

Here, h = a, = a and radius  =\[\sqrt{2}a\]

∴ Required equation of the circle:

\[\left( x - a \right)^2 + \left( y - a \right)^2 = \left( \sqrt{2}a \right)^2\]
\[\Rightarrow x^2 + a^2 - 2ax + y^2 + a^2 - 2ay = 2 a^2 \]
\[ \Rightarrow x^2 + y^2 - 2ay - 2ax = 0\]
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Advanced Concept of Circle - Standard Equation of a Circle
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Chapter 24: The circle - Exercise 24.1 [Page 21]

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RD Sharma Mathematics [English] Class 11
Chapter 24 The circle
Exercise 24.1 | Q 1.5 | Page 21

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