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Find the Equation of the Circle With:Centre (−2, 3) and Radius 4. - Mathematics

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Question

Find the equation of the circle with:

Centre (−2, 3) and radius 4.

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Solution

Let (hk) be the centre of a circle with radius a.
Thus, its equation will be \[\left( x - h \right)^2 + \left( y - k \right)^2 = a^2\]

Here, h = −2, = 3 and a = 4

∴ Required equation of the circle:

\[\left( x + 2 \right)^2 + \left( y - 3 \right)^2 = 4^2\]
\[\Rightarrow \left( x + 2 \right)^2 + \left( y - 3 \right)^2 = 16\]
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Advanced Concept of Circle - Standard Equation of a Circle
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Chapter 24: The circle - Exercise 24.1 [Page 21]

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RD Sharma Mathematics [English] Class 11
Chapter 24 The circle
Exercise 24.1 | Q 1.1 | Page 21

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