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The equation of a circle with origin as centre and passing through the vertices of an equilateral triangle whose median is of length 3a is ______. - Mathematics

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Question

The equation of a circle with origin as centre and passing through the vertices of an equilateral triangle whose median is of length 3a is ______.

Options

  • x2 + y2 = 9a2

  • x2 + y2 = 16a2

  • x2 + y2 = 4a2

  • x2 + y2 = a2

MCQ
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Solution

The equation of a circle with origin as centre and passing through the vertices of an equilateral triangle whose median is of length 3a is x2 + y2 = 4a2.

Explanation:

Let ABC be an equilateral triangle in which median AD = 3a.

Centre of the circle is same as the centroid of the triangle

i.e., (0, 0)

AG : GD = 2 : 1

So, AG = `2/3` AD = `2/3 xx 3a = 2a`

∴ The equation of the circle is (x – 0)2 + (y – 0)2 = (2a)2

⇒ x2 + y2 = 4a2

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Advanced Concept of Circle - Standard Equation of a Circle
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Chapter 11: Conic Sections - Exercise [Page 206]

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NCERT Exemplar Mathematics [English] Class 11
Chapter 11 Conic Sections
Exercise | Q 50 | Page 206

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