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If the Circle X2 + Y2 + 2ax + 8y + 16 = 0 Touches X-axis, Then the Value of a is

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Question

If the circle x2 + y2 + 2ax + 8y + 16 = 0 touches x-axis, then the value of a is

Options

  • ± 16

  • ±4

  • ± 8

  • ±1

MCQ
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Solution

± 4

The equation of the circle is x2 + y2 + 2ax + 8y + 16 = 0.
Its centre is \[\left( - a, - 4 \right)\] and its radius is a units.
Since the circle touches the x-axis, we have:

\[\sqrt{\left( - a + a \right)^2 + \left( 4 - 0 \right)^2} = a\]

⇒ \[a = \pm 4\]

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Advanced Concept of Circle - Standard Equation of a Circle
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Chapter 24: The circle - Exercise 24.6 [Page 39]

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RD Sharma Mathematics [English] Class 11
Chapter 24 The circle
Exercise 24.6 | Q 13 | Page 39

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