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Question
Find df for f(x) = x2 + 3x and evaluate it for x = 2 and dx = 0.1
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Solution
y = f(x) = x2 + 3x
dy = (2x + 3) dx
dy {when x = 2 and ate = 0.1} = [2(2) + 3](0.1)
= 7(0.1)
= 0.7
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