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Tamil Nadu Board of Secondary EducationHSC Science Class 12

Use the linear approximation to find approximate values of 263 - Mathematics

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Question

Use the linear approximation to find approximate values of `root(3)(26)`

Sum
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Solution

f(x) = x^(1/3), f(x0) = `(27)^(1/3)` = 2 Δx = – 1

We know that

f(x0 + Δx) = f(x0) + f’(x0) Δx

`(26)^(1/3) = 3 + 1/(3(27)^(2/3)) xx - 1`

= `3 + 1/27 xx - 1`

= `3 - 1/27`

= 3 – 0.370

`(26)^(1/3)` = 2.963

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Linear Approximation and Differentials
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Chapter 8: Differentials and Partial Derivatives - Exercise 8.1 [Page 64]

APPEARS IN

Samacheer Kalvi Mathematics - Volume 1 and 2 [English] Class 12 TN Board
Chapter 8 Differentials and Partial Derivatives
Exercise 8.1 | Q 2. (iii) | Page 64

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