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Question
A sphere is made of ice having radius 10 cm. Its radius decreases from 10 cm to 9.8 cm. Find approximations for the following:
Change in the volume
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Solution
Given r = 10
dr = 10 – 9.8 = 0.2
Volume v = `4/3 pi"r"^3`
dv = `4/3 * 3pi"r"^2"dv"`
Change in thhe volume
v(10) – v(9.8) = 4π(10)2(0.2)
= 80π cm3
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