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Tamil Nadu Board of Secondary EducationHSC Science Class 12

Let f(x) = x3. Find the linear approximation at x = 27. Use the linear approximation to approximate 27.23

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Question

Let f(x) = `root(3)(x)`. Find the linear approximation at x = 27. Use the linear approximation to approximate `root(3)(27.2)`

Sum
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Solution

x = 27

f(x) = `root(3)(27)` = 3

We need to find the value of `root(3)(27.2)`

We know that

f(x0 + Δx) = f(x0) + f'(x0) Δx

f(27.2) = `3 + 1/(3x^(2/3)) xx 0.2`

= `3 + 1/(3(27)^(2/3)) xx 0.2`

= `3 + 1/(3 xx 9) x 0.2`

= `3 + 0.2/27`

= `3 + 2/270`

= 3 + 0.0074

= 3.0074

∴ Approximate value of `root(3)(27.2)` = 3.0074

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Linear Approximation and Differentials
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Chapter 8: Differentials and Partial Derivatives - Exercise 8.1 [Page 64]

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Samacheer Kalvi Mathematics - Volume 1 and 2 [English] Class 12 TN Board
Chapter 8 Differentials and Partial Derivatives
Exercise 8.1 | Q 1 | Page 64

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