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Let f(x) = x3. Find the linear approximation at x = 27. Use the linear approximation to approximate 27.23 - Mathematics

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प्रश्न

Let f(x) = `root(3)(x)`. Find the linear approximation at x = 27. Use the linear approximation to approximate `root(3)(27.2)`

योग
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उत्तर

x = 27

f(x) = `root(3)(27)` = 3

We need to find the value of `root(3)(27.2)`

We know that

f(x0 + Δx) = f(x0) + f'(x0) Δx

f(27.2) = `3 + 1/(3x^(2/3)) xx 0.2`

= `3 + 1/(3(27)^(2/3)) xx 0.2`

= `3 + 1/(3 xx 9) x 0.2`

= `3 + 0.2/27`

= `3 + 2/270`

= 3 + 0.0074

= 3.0074

∴ Approximate value of `root(3)(27.2)` = 3.0074

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Linear Approximation and Differentials
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 8: Differentials and Partial Derivatives - Exercise 8.1 [पृष्ठ ६४]

APPEARS IN

सामाचीर कलवी Mathematics - Volume 1 and 2 [English] Class 12 TN Board
अध्याय 8 Differentials and Partial Derivatives
Exercise 8.1 | Q 1 | पृष्ठ ६४

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