Advertisements
Advertisements
Question
Factorise the following, using the identity a2 – 2ab + b2 = (a – b)2.
4a2 – 4ab + b2
Sum
Advertisements
Solution
We have,
4a2 – 4ab + b2
= (2a)2 – 2 × 2a × b + b2
= (2a – b)2
= (2a – b)(2a – b)
shaalaa.com
Is there an error in this question or solution?
Chapter 7: Algebraic Expression, Identities and Factorisation - Exercise [Page 234]
APPEARS IN
RELATED QUESTIONS
Expand (2)2p − 3q
Factorise the following expressions
y2 – 10y + 25
Factors of 4 – m2 are
Expand the following square, using suitable identities
(xyz – 1)2
a2 – b2 is equal to ______.
Square of 9x – 7xy is ______.
Using suitable identities, evaluate the following.
(9.9)2
Factorise the following, using the identity a2 – 2ab + b2 = (a – b)2.
x2 – 10x + 25
Factorise the following, using the identity a2 – 2ab + b2 = (a – b)2.
y2 – 14y + 49
Factorise the following.
x2 + 4x – 77
