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Question
Expand `("a"-1/"a")^2`
Sum
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Solution
It is known that, (a + b)2 = a2 + 2ab + b2 and (a − b)2 = a2 − 2ab + b2.
`("a"-1/"a")^2`
= `("a")^2-2xx("a")xx(1/"a")+(1/"a")^2`
= `"a"^2-2+1/"a"^2`
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