Advertisements
Advertisements
Question
Expand `("a"-1/"a")^2`
Sum
Advertisements
Solution
It is known that, (a + b)2 = a2 + 2ab + b2 and (a − b)2 = a2 − 2ab + b2.
`("a"-1/"a")^2`
= `("a")^2-2xx("a")xx(1/"a")+(1/"a")^2`
= `"a"^2-2+1/"a"^2`
shaalaa.com
Is there an error in this question or solution?
RELATED QUESTIONS
Evaluate the following, using suitable identity
9982
(a – b)2 + ______ = a2 – b2
1032 – 1022 = ______ × (103 – 102) = ______.
Factorise the following, using the identity a2 – 2ab + b2 = (a – b)2.
4a2 – 4ab + b2
Factorise the following, using the identity a2 – 2ab + b2 = (a – b)2.
4y2 – 12y + 9
Factorise the following, using the identity a2 – 2ab + b2 = (a – b)2.
a2y3 – 2aby2 + b2y
Factorise the following.
p2 – 13p – 30
Factorise the following.
a2 – 16p – 80
If m – n = 16 and m2 + n2 = 400, then find mn.
Verify the following:
(a – b)(a – b)(a – b) = a3 – 3a2b + 3ab2 – b3
