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Question
Factorise the following, using the identity a2 – 2ab + b2 = (a – b)2.
p2y2 – 2py + 1
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Solution
We have,
p2y2 – 2py + 1
= (py)2 – 2 × py × 1 + 12
= (py – 1)2
= (py – 1)(py – 1)
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