Advertisements
Advertisements
Question
Factorise the following, using the identity a2 – 2ab + b2 = (a – b)2.
p2y2 – 2py + 1
Advertisements
Solution
We have,
p2y2 – 2py + 1
= (py)2 – 2 × py × 1 + 12
= (py – 1)2
= (py – 1)(py – 1)
APPEARS IN
RELATED QUESTIONS
Expand (7m − 4)2
Expand the following square, using suitable identities
(xyz – 1)2
Show that (m – n)2 + (m + n)2 = 2(m2 + n2)
Factorise the following, using the identity a2 – 2ab + b2 = (a – b)2.
x2 – 8x + 16
Factorise the following, using the identity a2 – 2ab + b2 = (a – b)2.
y2 – 14y + 49
Factorise the following, using the identity a2 – 2ab + b2 = (a – b)2.
4a2 – 4ab + b2
Factorise the following, using the identity a2 – 2ab + b2 = (a – b)2.
4y2 – 12y + 9
Factorise the following.
y2 + 4y – 21
The curved surface area of a cylinder is 2π(y2 – 7y + 12) and its radius is (y – 3). Find the height of the cylinder (C.S.A. of cylinder = 2πrh).
If `x - 1/x = 7` then find the value of `x^2 + 1/x^2`.
