Advertisements
Advertisements
Question
Factorise the following, using the identity a2 – 2ab + b2 = (a – b)2.
a2y2 – 2aby + b2
Sum
Advertisements
Solution
We have,
a2y2 – 2aby + b2
= (ay)2 – 2 × ay × b + b2
= (ay – b)2
= (ay – b)(ay – b)
shaalaa.com
Is there an error in this question or solution?
Chapter 7: Algebraic Expression, Identities and Factorisation - Exercise [Page 234]
APPEARS IN
RELATED QUESTIONS
Expand (7m − 4)2
Expand (5p – 1)2
(a – 1)2 = a2 – 1
Expand the following square, using suitable identities
(xyz – 1)2
Factorise the following, using the identity a2 – 2ab + b2 = (a – b)2.
p2y2 – 2py + 1
Factorise the following, using the identity a2 – 2ab + b2 = (a – b)2.
`9y^2 - 4xy + (4x^2)/9`
Factorise the following.
y2 + 4y – 21
Factorise the following.
x2 – 17x + 60
Verify the following:
(a – b)(a – b)(a – b) = a3 – 3a2b + 3ab2 – b3
Subtract b(b2 + b – 7) + 5 from 3b2 – 8 and find the value of expression obtained for b = – 3.
